.267x^2-4.5x+17.4=0

Solution for .267x^2-4.5x+17.4=0 equation:

.267x^2-4.5x+17.4=0

a = .267; b = -4.5; c = +17.4;
Δ = b2-4ac
Δ = -4.52-4·.267·17.4
Δ = 1.6668
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.5)-\sqrt{1.6668}}{2*.267}=\frac{4.5-\sqrt{1.6668}}{0.534}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.5)+\sqrt{1.6668}}{2*.267}=\frac{4.5+\sqrt{1.6668}}{0.534}
$